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5(1-x)^2-6(^2-3x-7)=x(x-3)-2x(x+5)-2
We move all terms to the left:
5(1-x)^2-6(^2-3x-7)-(x(x-3)-2x(x+5)-2)=0
We add all the numbers together, and all the variables
5(-1x+1)^2-6(^2-3x-7)-(x(x-3)-2x(x+5)-2)=0
We multiply parentheses
5(-1x+1)^2+18x-(x(x-3)-2x(x+5)-2)+42-=0
We calculate terms in parentheses: -(x(x-3)-2x(x+5)-2), so:We add all the numbers together, and all the variables
x(x-3)-2x(x+5)-2
We multiply parentheses
x^2-2x^2-3x-10x-2
We add all the numbers together, and all the variables
-1x^2-13x-2
Back to the equation:
-(-1x^2-13x-2)
-(-1x^2-13x-2)+18x+5(-1x+1)^2=0
We get rid of parentheses
1x^2+13x+18x+5(-1x+1)^2+2=0
We add all the numbers together, and all the variables
x^2+31x+5(-1x+1)^2+2=0
We move all terms containing x to the left, all other terms to the right
x^2+31x+5(-1x+1)^2=-2
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